A circular region of radius R has uniform magnetic field B⃗=(B₀+B₀t)(-k̂). A charged particle of charge q and mass m is at distance r>R from the centre. Find its acceleration at t=0.

Question

G1 Physics · Accepted Answer

For r>R, Faraday’s law gives E(2πr)=πR²(dB/dt). Here dB/dt=B₀, so E=B₀R²/(2r). Initially v=0, so the magnetic force is zero. Hence a=qE/m=qB₀R²/(2mr). Therefore option A.

A circular region of radius R has uniform magnetic field B⃗=(B₀+B₀t)(-k̂). A charged particle of charge q and mass m is at distance r&gt;R from the centre. Find its acceleration at t=0.

A circular region of radius R has uniform magnetic field B⃗=(B₀+B₀t)(-k̂). A charged particle of charge q and mass m is at distance r>R from the centre. Find its acceleration at t=0.