Physics · AC Circuits
JEE MainsNEET
In the shown series LR circuit, the applied voltage is V=V₀sinωt+(V₀/2)cosωt. The current amplitude is:
Options
√5V₀/[2√(ω²L²+R²)]
V₀/[2√(ω²L²+R²)]
√5V₀/[2√(ω²L²-R²)]
√5V₀/[2√(R²-ω²L²)]
