When resistance R is in series with element A, current lags voltage by θ₁. With element B, current leads voltage by θ₂. When R, A and B are all in series, current leads voltage by θ. Then:
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Question

When resistance R is in series with element A, current lags voltage by θ₁. With element B, current leads voltage by θ₂. When R, A and B are all in series, current leads voltage by θ. Then:

G1 Physics · Accepted Answer

Let Xₐ be the inductive reactance and Xᵦ the capacitive reactance. tanθ₁=Xₐ/R and tanθ₂=Xᵦ/R. Hence tanθ=(Xᵦ−Xₐ)/R=tanθ₂−tanθ₁.