An applied voltage is v=200√2 sin(ωt+15°) V and current is i=2 sin(ωt+π/4) A. The average power consumed is:
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An applied voltage is v=200√2 sin(ωt+15°) V and current is i=2 sin(ωt+π/4) A. The average power consumed is:

G1 Physics · Accepted Answer

Vᵣₘₛ=200 V and Iᵣₘₛ=√2 A. Phase difference is 45°−15°=30°. Hence P=VrmsIrmscos30°=100√6 W. Therefore C.