A right-angled triangular wire loop abc moves with uniform speed v in its plane through a uniform magnetic field perpendicular to the plane. Find the induced emf in (a) loop abc, (b) segment bc, (c) segment ac and (d) segment ab.

Question

G1 Physics · Accepted Answer

The entire closed loop translates rigidly in uniform B, so net loop emf is zero. For each segment, ε=∫(v⃗×B⃗)·dℓ⃗. Segment bc has magnitude vB·bc with c at higher potential; segment ac is perpendicular to v⃗×B⃗ so zero; segment ab then has equal magnitude with a positive so the loop sum is zero. Hence A.