The position of a particle is x=A cos(ωt-φ) under force F=F₀ cosωt. What is the average power delivered by this force?
Options

Question

The position of a particle is x=A cos(ωt−φ) under force F=F₀ cosωt. What is the average power delivered by this force?

G1 Physics · Accepted Answer

v=−Aω sin(ωt−φ). Therefore P=Fv, and averaging over one cycle gives P̄=(F₀Aω/2)sinφ. Hence option A.