An LCR circuit is equivalent to a damped oscillator. The capacitor is initially charged to Q₀ and then connected to L and R. For two inductances L₁>L₂, which graph correctly shows Qₘₐₓ² versus time?

Question

G1 Physics · Accepted Answer

The envelope of charge decays exponentially. Larger L gives a smaller damping rate R/(2L), so the L₁ curve decays more slowly than the L₂ curve. The graph with this ordering is Image 3. Hence option C.

An LCR circuit is equivalent to a damped oscillator. The capacitor is initially charged to Q₀ and then connected to L and R. For two inductances L₁&gt;L₂, which graph correctly shows Qₘₐₓ² versus time?

An LCR circuit is equivalent to a damped oscillator. The capacitor is initially charged to Q₀ and then connected to L and R. For two inductances L₁>L₂, which graph correctly shows Qₘₐₓ² versus time?