An AC source V=V₀(sinωt+sin3ωt) is connected in series with R and C. The current is i=i₁sin(ωt+φ₁)+i₂sin(3ωt+φ₂). Then:
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Question

An AC source V=V₀(sinωt+sin3ωt) is connected in series with R and C. The current is i=i₁sin(ωt+φ₁)+i₂sin(3ωt+φ₂). Then:

G1 Physics · Accepted Answer

Use Xₗ=ωL, X꜀=1/(ωC), Z=√[R²+(Xₗ−X꜀)²] and Iᵣₘₛ=Vᵣₘₛ/Z. The circuit condition gives i₁ < i₂.