In the figure shown all the surfaces are frictionless, and mass of the block, m = 1 kg. The block and wedge are held initially at rest. Now wedge is given a horizontal acceleration of 10 m/s² by applying a force on the wedge, so that the block does not slip on the wedge. Then work done by the normal force in ground frame on the block in √3 seconds is :

Question

G1 Physics · Accepted Answer

Because the block does not slip on the wedge, it shares the wedge's horizontal acceleration 10 m/s². In √3 s, displacement is s=½at²=15 m and the normal is the force doing the required horizontal work ma·s=10×15=150 J. Hence C.