The potential energy of a 2 kg particle moving along the x-axis is U(x)=(4.0 J/m²)x²+(1.0 J/m⁴)x⁴. When the particle is at x=1.0 m, find the magnitude of its acceleration in m/s². Only conservative forces act.

Physics · Work , Power and Energy · conservative force and potential energy

JEE Mains

The potential energy of a 2 kg particle moving along the x-axis is U(x)=(4.0 J/m²)x²+(1.0 J/m⁴)x⁴. When the particle is at x=1.0 m, find the magnitude of its acceleration in m/s². Only conservative forces act.