Consider Fraunhofer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum, the phase difference (in radians) between the wavelets from the opposite edges of the slit is:
Options

Question

Consider Fraunhofer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum, the phase difference (in radians) between the wavelets from the opposite edges of the slit is:

Options

G1 Physics · Accepted Answer

For the first single-slit minimum, path difference between wavelets from the two slit edges is a sinθ=λ. The corresponding phase difference is 2π(a sinθ/λ)=2π. Hence option B.