Light of wavelength 600 nm passes through a single slit of width 4×10⁻⁴ m. The screen is 2 m away. The source figure marks the width s of the central diffraction maximum. Find s.

Question

G1 Physics · Accepted Answer

For a single slit, first minima occur at y₁=λD/a. The central maximum width is 2y₁, so s=2λD/a=2(600×10⁻⁹)(2)/(4×10⁻⁴)=6×10⁻³ m=0.006 m. Option D.