In a YDSE, λ=4000 Å, D=2 m and d=1 mm. Three slabs are available: slab 1 has thickness 2 mm and μ=2; slab 2 has thickness 1 mm and μ=3; slab 3 has thickness 4 mm and μ=3/2. Match the stated slab placements with the resulting fringe properties.

Physics · Wave Optics

JEE Advanced

In a YDSE, λ=4000 Å, D=2 m and d=1 mm. Three slabs are available: slab 1 has thickness 2 mm and μ=2; slab 2 has thickness 1 mm and μ=3; slab 3 has thickness 4 mm and μ=3/2. Match the stated slab placements with the resulting fringe properties.

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List 1

  1. (A) Slab 1 (2 mm, μ=2) placed before S₁

  2. (B) Slab 2 (1 mm, μ=3) placed before S₂ in addition to A

  3. (C) Slab 3 (4 mm, μ=3/2) placed before slab 1 in addition to B

  4. .

List 2

  1. (P) Central maximum at C

  2. (Q) Central maximum above C

  3. (R) Fringe width = 0.8 mm

  4. (S) Number of fringes crossing centre due to slab placement = 5000

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