A plane electromagnetic wave in vacuum has B=B₀ sin[2π×2×10¹⁵(t-x/c)] with B₀=100×10⁻⁶ T. Find the maximum electric field. Take c=3×10⁸ m s⁻¹.
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Question

A plane electromagnetic wave in vacuum has B=B₀ sin[2π×2×10¹⁵(t−x/c)] with B₀=100×10⁻⁶ T. Find the maximum electric field. Take c=3×10⁸ m s⁻¹.

G1 Physics · Accepted Answer

For an electromagnetic wave in vacuum, E₀=cB₀. With B₀=100×10⁻⁶ T, E₀=3×10⁸×100×10⁻⁶=3×10⁴ N C⁻¹. Option D.