A liquid in a beaker has temperature θ(t) at time t and θ0 is temperature of surroundings, then according to Newton's law of cooling the correct graph between loge (θ - θ0) and t is :
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Question

A liquid in a beaker has temperature θ(t) at time t and θ0 is temperature of surroundings, then according to Newton's law of cooling the correct graph between loge (θ - θ0) and t is :

G1 Physics · Accepted Answer

Use Stefan-Boltzmann law P=eσA(T⁴-Tₛ⁴), Wien's law λₘT=b, or Newton's law of cooling dθ/dt=-k(θ-θₛ), as applicable. Evaluating the given data/statements gives B: Image 2. Therefore the correct answer is B.