A copper calorimeter of mass 100 gm contains 200 gm of a mixture of ice and water. Steam at 100°C under normal pressure is passed into the calorimeter and the temperature of the mixture is allowed to rise to 50°C. If the mass of the calorimeter and its contents is now 330 gm, what was the ratio of ice and water in the beginning? Neglect heat losses. Given : Specific heat capacity of copper = 0.42 ×10³ J kg⁻¹K⁻¹, Specific heat capacity of water = 4.2 ×10³ J kg⁻¹K⁻¹, Specific heat of fusion of ice = 3.36 ×10⁵ J kg⁻¹ Latent heat of condensation of steam = 22.5 ×10⁵ J kg⁻¹ Which of the following gives the correct final result?
Physics · Thermodynamics
A copper calorimeter of mass 100 gm contains 200 gm of a mixture of ice and water. Steam at 100°C under normal pressure is passed into the calorimeter and the temperature of the mixture is allowed to rise to 50°C. If the mass of the calorimeter and its contents is now 330 gm, what was the ratio of ice and water in the beginning? Neglect heat losses. Given : Specific heat capacity of copper = 0.42 ×10³ J kg⁻¹K⁻¹, Specific heat capacity of water = 4.2 ×10³ J kg⁻¹K⁻¹, Specific heat of fusion of ice = 3.36 ×10⁵ J kg⁻¹ Latent heat of condensation of steam = 22.5 ×10⁵ J kg⁻¹ Which of the following gives the correct final result?
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