In a thermodynamic process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by T Δ X \Delta X Δ X , where T is temperature of the system and Δ X \Delta X Δ X is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monatomic ideal gas X= 3 2 \frac32 2 3 ​ R ln ⁡ [ T T A ] \ln\left\lbrack\frac{T}{T_{A}}\right\rbrack ln [ T A ​ T ​ ] + [ V V A ] \left\lbrack\frac{V}{V_{A}}\right\rbrack [ V A ​ V ​ ] R ln ⁡ \ln ln RIn. Here, R is gas constant, V is volume of gas, Ta and Va are constants.Match the quantities in List-I with the expressions in List-II.

Physics · Thermodynamics

JEE Advanced 2019

In a thermodynamic process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by TΔX\Delta X, where T is temperature of the system and ΔX\Delta X is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monatomic ideal gas X=32\frac32Rln⁡[TTA]\ln\left\lbrack\frac{T}{T_{A}}\right\rbrack+[VVA]\left\lbrack\frac{V}{V_{A}}\right\rbrackRln⁡\ln

RIn. Here, R is gas constant, V is volume of gas, Ta and Va are constants.Match the quantities in List-I with the expressions in List-II.

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List 1

  1. I. Work done in 1→2→3

  2. II. Change in internal energy in 1→2→3

  3. III. Heat absorbed in 1→2→3

  4. IV. Heat absorbed in 1→2

  5. V.

  6. VI.

List 2

  1. (P) (RT₀/3)ln 2

  2. (Q) RT₀/3

  3. (R) RT₀

  4. (S) 4RT₀/3

  5. (T) (RT₀/3)(3+ln 2)

  6. (U) 5RT₀/6

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