One mole of an ideal diatomic gas is taken through the cycle as shown in the figure. 1 → 2 : isochoric process 2 → 3 : straight line on P-V diagram 3 → 1 : isobaric process The average molecular speed of the gas in the states 1, 2 and 3 are in the ratio

Question

G1 Physics · Accepted Answer

Use PV=nRT, U=(f/2)nRT, γ=1+2/f and vᵣₘₛ=√(3RT/M). At the same temperature, average translational kinetic energy depends only on T. Evaluating the given data/statements gives 1 : 2 : 2. Therefore the correct answer is A.