The K, L and M shell energies of platinum are approximately -78 keV, -12 keV and -3 keV. Find the ratio λ(Kα)/λ(Kβ).
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Question

The K, L and M shell energies of platinum are approximately −78 keV, −12 keV and −3 keV. Find the ratio λ(Kα)/λ(Kβ).

G1 Physics · Accepted Answer

Kα energy = 78−12 = 66 keV and Kβ energy = 78−3 = 75 keV. Since λ ∝ 1/E, λ(Kα)/λ(Kβ) = 75/66 = 25/22. Correct answer: D.