Let the potential energy of a hydrogen atom in the ground state be zero. Then its energy in the first excited state will be :
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Let the potential energy of a hydrogen atom in the ground state be zero. Then its energy in the first excited state will be :

G1 Physics · Accepted Answer

Step 1: For a hydrogen-like atom, Eₙ = −13.6Z²/n² eV and photon energy is ΔE = 13.6Z²|1/n₂²−1/n₁²| = hc/λ. Step 2: Use the stated transition/excitation condition to obtain the required value. Final: C: 23.8 eV.