A photon of 10.2 eV energy collides with a hydrogen atom in ground state inelastically. After few microseconds one more photon of energy 15 eV collides with the same hydrogen atom. Then what can be detected by a suitable detector.
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Question

A photon of 10.2 eV energy collides with a hydrogen atom in ground state inelastically. After few microseconds one more photon of energy 15 eV collides with the same hydrogen atom. Then what can be detected by a suitable detector.

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G1 Physics · Accepted Answer

Step 1: For a hydrogen-like atom, Eₙ = −13.6Z²/n² eV and photon energy is ΔE = 13.6Z²|1/n₂²−1/n₁²| = hc/λ. Step 2: Use the stated transition/excitation condition to obtain the required value. Final: A: one photon of 10.2 eV and an electron of energy 1.4 eV.