The ionization energy of the electron in the hydrogen atom in its ground state is 13.6 eV. The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between :
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Question

The ionization energy of the electron in the hydrogen atom in its ground state is 13.6 eV. The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between :

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G1 Physics · Accepted Answer

Step 1: For a hydrogen-like atom, Eₙ = −13.6Z²/n² eV and photon energy is ΔE = 13.6Z²|1/n₂²−1/n₁²| = hc/λ. Step 2: Use the stated transition/excitation condition to obtain the required value. Final: A: n = 4 to n = 3 states.