The accelerating potential (V) applied between a photocathode and the respective anode is such that the fastest photoelectron can fly only one fourth of the distance between the cathode and the anode. If the distance between photocathode and anode is reduced to (1/4)th of the original value while maintaining the accelerating potential constant, then:
Select all that apply

Question

The accelerating potential (V) applied between a photocathode and the respective anode is such that the fastest photoelectron can fly only one fourth of the distance between the cathode and the anode. If the distance between photocathode and anode is reduced to (1/4)th of the original value while maintaining the accelerating potential constant, then:

Select all that apply

G1 Physics · Accepted Answer

Step 1: Use Eγ = hν = hc/λ and Kₘₐₓ = hν−φ = eVₛ. Step 2: Apply the threshold condition Kₘₐₓ = 0 where required and use the given photon energy/frequency. Final: B: The fastest electron will reach upto one fourth of the new distance between the cathode and the anode.; C: Kinetic energy of the fastest photoelectron emitted from photocathode will not change due to change in plate separation (keeping V constant)..