A ²²⁶₈₈Ra nucleus at rest undergoes α-decay to excited ²²²₈₆Rn. The α-particle kinetic energy is 4.44 MeV. The daughter then emits a γ photon to reach its ground state. Given m(²²⁶Ra)=226.005u, m(²²²Rn)=222.000u, mα=4.000u and 1u=931 MeV c⁻², find the γ energy in keV.
Physics · Nuclear physics
A ²²⁶₈₈Ra nucleus at rest undergoes α-decay to excited ²²²₈₆Rn. The α-particle kinetic energy is 4.44 MeV. The daughter then emits a γ photon to reach its ground state. Given m(²²⁶Ra)=226.005u, m(²²²Rn)=222.000u, mα=4.000u and 1u=931 MeV c⁻², find the γ energy in keV.