In a photoelectric experiment, 5 eV photons fall on a cathode of work function 3 eV. For intensity I₁ = 10¹⁵ m⁻² s⁻¹, the saturation current is 4.0 μA. Which graph correctly compares photocurrent versus anode voltage for intensity I₁ and I₂ = 2 × 10¹⁵ m⁻² s⁻¹? Image
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Question

In a photoelectric experiment, 5 eV photons fall on a cathode of work function 3 eV. For intensity I₁ = 10¹⁵ m⁻² s⁻¹, the saturation current is 4.0 μA. Which graph correctly compares photocurrent versus anode voltage for intensity I₁ and I₂ = 2 × 10¹⁵ m⁻² s⁻¹? Image

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G1 Physics · Accepted Answer

Step 1: Photon energy is Eγ = hc/λ and Einstein's equation is Kₘₐₓ = Eγ−φ. Step 2: If a stopping potential is involved, Kₘₐₓ = eVₛ. Step 3: Using the two stated cases eliminates φ or gives it directly. Final: A: Image 1.