The binding energy per nucleon of deuteron ²₁H and helium ⁴₂He is 1.1 MeV and 7 MeV, respectively. If two deuterons fuse to form one helium nucleus, the released energy is 236 × 10⁻ⁿ MeV. Find n.
Physics · Nuclear physics
JEE Mains Practice

Question

The binding energy per nucleon of deuteron ²₁H and helium ⁴₂He is 1.1 MeV and 7 MeV, respectively. If two deuterons fuse to form one helium nucleus, the released energy is 236 × 10⁻ⁿ MeV. Find n.

Physics · Nuclear physics

G1 Physics · Accepted Answer

Initial binding energy of two deuterons =4×1.1=4.4 MeV. Final helium binding =4×7=28 MeV. Released energy=23.6 MeV=236×10⁻¹ MeV, so n=1.