When two deuterons ²₁H fuse to form one helium nucleus ⁴₂He, 23.6 MeV is released. If the binding energy per nucleon of deuterium is 1.1 MeV, find the total binding energy of ⁴₂He.
Options

Question

When two deuterons ²₁H fuse to form one helium nucleus ⁴₂He, 23.6 MeV is released. If the binding energy per nucleon of deuterium is 1.1 MeV, find the total binding energy of ⁴₂He.

G1 Physics · Accepted Answer

Two deuterons contain four nucleons with initial total binding 4×1.1=4.4 MeV. Adding released energy 23.6 MeV gives helium binding energy 28 MeV. Correct answer: A.