Water is flowing steadily through a horizontal tube of non-uniform cross-section. If the pressure of water is 4 × 10⁴ N m⁻² at a point where cross-section is 0.02 m² and velocity of flow is 2 m s⁻¹, what is pressure at a point where cross-section reduces to 0.01 m².
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Question

Water is flowing steadily through a horizontal tube of non-uniform cross-section. If the pressure of water is 4 × 10⁴ N m⁻² at a point where cross-section is 0.02 m² and velocity of flow is 2 m s⁻¹, what is pressure at a point where cross-section reduces to 0.01 m².

Options

G1 Physics · Accepted Answer

Step 1: Continuity gives v₂ = v₁(A₁/A₂)=2×(0.02/0.01)=4 m s⁻¹. Step 2: Bernoulli in a horizontal pipe gives P₂=P₁+½ρ(v₁²−v₂²)=4×10⁴+500(4−16)=3.4×10⁴ Pa. Final answer: B.