A water jet is projected at an angle θ to the horizontal. At projection its cross-sectional area is S₁ and at the highest point it is S₂. The initial speed is u. Select the correct statement(s). Image
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Question

A water jet is projected at an angle θ to the horizontal. At projection its cross-sectional area is S₁ and at the highest point it is S₂. The initial speed is u. Select the correct statement(s). Image

Select all that apply

G1 Physics · Accepted Answer

Step 1: Continuity gives S₁u = S₂u cosθ at the highest point, so cosθ = S₁/S₂ and θ = cos⁻¹(S₁/S₂); A is true. Step 2: Projectile range is R = (u²/g)sin2θ = (2u²/g)(S₁/S₂)√[1−S₁²/S₂²], so B is true. The maximum height is u²sin²θ/(2g), not the expression in C, and the flow rate is S₁u, not S₂u. Correct answers: A, B.