Two vessels containing the same liquid are connected by a differential mercury manometer. The liquid density is 720 kg m⁻³, mercury density is 13600 kg m⁻³, the liquid-level difference shown is 0.1 m and the mercury-level difference is 0.32 m. Find the pressure difference between the vessels. Take g = 9.8 m s⁻². Image
Physics · Fluid Mechanics
JEE Mains Advanced

Question

Two vessels containing the same liquid are connected by a differential mercury manometer. The liquid density is 720 kg m⁻³, mercury density is 13600 kg m⁻³, the liquid-level difference shown is 0.1 m and the mercury-level difference is 0.32 m. Find the pressure difference between the vessels. Take g = 9.8 m s⁻². Image

Physics · Fluid Mechanics

G1 Physics · Accepted Answer

Step 1: Use hydrostatic equilibrium, P₂−P₁ = ρgΔh; in an accelerating fluid replace g by the effective acceleration where required. Step 2: Equate pressures at the same horizontal level or integrate pressure over the stated surface. Applying these relations to the given data gives 40.33. Final answer: 40.33.