A wooden block floats in water in a sealed container. When the container is at rest, 25% of the block is above the water. Consider the following five situation: (i) the container is lifted up at constant speed. (ii) the container is lowered at constant speed. (iii) the container is lifted up at an increasing speed. (iv) the container is lowered at a decreasing speed. (v) the air pressure above the water in the container is increased. What happens in each situation?
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Question

A wooden block floats in water in a sealed container. When the container is at rest, 25% of the block is above the water. Consider the following five situation: (i) the container is lifted up at constant speed. (ii) the container is lowered at constant speed. (iii) the container is lifted up at an increasing speed. (iv) the container is lowered at a decreasing speed. (v) the air pressure above the water in the container is increased. What happens in each situation?

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G1 Physics · Accepted Answer

Step 1: Use hydrostatic equilibrium, P₂−P₁ = ρgΔh; in an accelerating fluid replace g by the effective acceleration where required. Step 2: Equate pressures at the same horizontal level or integrate pressure over the stated surface. Applying these relations to the given data gives D: 75% of block is submerged in all situation.. Final answer: D.