Two triangular wave pulses are traveling towards each other on a stretched string as shown in figure. 1cm v = 2 cm s⁻¹ 1cm 1cm v = 2 cm s⁻¹ 1 cm 2cm 1cm 1cm t = 0 Speed of each pulse is 2 cm s⁻¹. Find maximum displacement of particle of string at t = 1s. The leading edges of the pulses are 2.00 cm apart at t = 0.

Physics · Wave Motion

JEE MainsAdvanced

Two triangular wave pulses are traveling towards each other on a stretched string as shown in figure. 1cm v = 2 cm s⁻¹ 1cm 1cm v = 2 cm s⁻¹ 1 cm 2cm 1cm 1cm t = 0 Speed of each pulse is 2 cm s⁻¹. Find maximum displacement of particle of string at t = 1s. The leading edges of the pulses are 2.00 cm apart at t = 0.

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