In a resonance tube water is filled so that height of air column is 0.1 m when it resonates in its fundamental mode. Now water is removed so that the height of air column becomes 0.35 m and it resonates with next higher frequency. Then end correction is:
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Question

In a resonance tube water is filled so that height of air column is 0.1 m when it resonates in its fundamental mode. Now water is removed so that the height of air column becomes 0.35 m and it resonates with next higher frequency. Then end correction is:

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G1 Physics · Accepted Answer

Step 1: Open-open pipe: fₙ = nv/(2effective length). Closed-open pipe: fₙ = (2n−1)v/(4effective length). Step 2: Include end correction in effective length where stated; successive resonances differ by λ/2. Step 3: Apply the harmonic/resonance condition. Final: B: 0.025 m.