A semi-infinite insulating rod has linear charge density λ. The electric field at the point P shown in figure is :-

Options

• Option A

  $\frac{2\lambda^2}{\left(4\pi\varepsilon_{\omicron}r\right)^2}$ at $45^{\omicron}$ with AB

• Option B

  $\frac{\sqrt2\lambda}{4\pi\varepsilon_{\omicron}r^2}$ at $45^{\omicron}$ with AB

• Option C

  $\frac{\sqrt2\lambda}{4\pi\varepsilon_{\omicron}r}$ at $45^{\omicron}$ with AB

• Option D

  $\frac{\sqrt2\lambda}{4\pi\varepsilon_{\omicron}r}$ at perpendicular with AB