In the electric field shown, three equipotential surfaces have potentials V₁, V₂ and V₃. The field magnitude depends on x as E = 2x² V m⁻¹, and V₁ - V₂ = V₂ - V₃. If the separations are x₁ and x₂ as shown, then:

Physics · Electrostatic

JEE MainsAdvanced

In the electric field shown, three equipotential surfaces have potentials V₁, V₂ and V₃. The field magnitude depends on x as E = 2x² V m⁻¹, and V₁ - V₂ = V₂ - V₃. If the separations are x₁ and x₂ as shown, then:

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