An electric dipole of dipole moment p ⃗ \vec{p} p is placed at the origin along the x-axis. At point P, the position vector makes angle θ with the x-axis. Find the angle made by the electric field with the x-axis. Given tanα = (1/2)tanθ.
Physics · Electrostatic
JEE Mains Advanced

Question

An electric dipole of dipole moment p ⃗ \vec{p} p is placed at the origin along the x-axis. At point P, the position vector makes angle θ with the x-axis. Find the angle made by the electric field with the x-axis. Given tanα = (1/2)tanθ.

Physics · Electrostatic

G1 Physics · Accepted Answer

Step 1: Use 𝐩 = Σqᵢ𝐫ᵢ (for net zero charge), V = [1/(4πε₀)](𝐩·𝐞ᵣ/r²) and 𝛕 = 𝐩×𝐄 as needed. Step 2: Resolve 𝐩 into components and use the small-angle approximation τ ≈ -pEθ for oscillations. Step 3: Substitute the given geometry and simplify. Final: C: θ + α.

An electric dipole of dipole moment p ⃗ \vec{p} p ​ is placed at the origin along the x-axis. At point P, the position vector makes angle θ with the x-axis. Find the angle made by the electric field with the x-axis. Given tanα = (1/2)tanθ.

An electric dipole of dipole moment p ⃗ \vec{p} p is placed at the origin along the x-axis. At point P, the position vector makes angle θ with the x-axis. Find the angle made by the electric field with the x-axis. Given tanα = (1/2)tanθ.