A circular disc of radius R has surface charge density σ(r) = σ₀(1 - r/R). A very large spherical Gaussian surface encloses the entire disc and has flux φ₀. A second sphere of radius R/4, concentric with the disc, has flux φ. Find φ₀/φ.

Physics · Electrostatic · electric flux and gauss law

JEE Advanced 2020

A circular disc of radius R has surface charge density σ(r) = σ₀(1 - r/R). A very large spherical Gaussian surface encloses the entire disc and has flux φ₀. A second sphere of radius R/4, concentric with the disc, has flux φ. Find φ₀/φ.