A Vernier callipers has 1 MSD = 1 mm and 10 VSD = 9 MSD. With jaws closed, the 7th Vernier division coincides and the Vernier zero lies to the right of the main-scale zero. For a cylinder, the Vernier zero lies between 3.1 cm and 3.2 cm and the 4th Vernier division coincides. Find the corrected length.
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Question

A Vernier callipers has 1 MSD = 1 mm and 10 VSD = 9 MSD. With jaws closed, the 7th Vernier division coincides and the Vernier zero lies to the right of the main-scale zero. For a cylinder, the Vernier zero lies between 3.1 cm and 3.2 cm and the 4th Vernier division coincides. Find the corrected length.

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G1 Physics · Accepted Answer

LC=1 MSD−1 VSD=1−0.9=0.1 mm=0.01 cm. Positive zero error =7×0.01=0.07 cm. Observed reading =3.1+4×0.01=3.14 cm. Corrected length =3.14−0.07=3.07 cm. Correct answer: D.