To determine g, the period is T = 2π√[7(R-r)/(5g)]. R=(60±1) mm and r=(10±1) mm. Five measured periods are 0.52,0.56,0.57,0.54,0.59 s; watch LC=0.01 s. Select the correct statements.
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Question

To determine g, the period is T = 2π√[7(R−r)/(5g)]. R=(60±1) mm and r=(10±1) mm. Five measured periods are 0.52,0.56,0.57,0.54,0.59 s; watch LC=0.01 s. Select the correct statements.

G1 Physics · Accepted Answer

Mean period is about 0.556 s. Mean absolute error is about 0.020 s, so percentage error in T is ≈3.6%, giving B. For r=10±1 mm, relative error is 10%, so A. Since g∝(R−r)/T², Δg/g≈Δ(R−r)/(R−r)+2ΔT/T≈(2/50)+2(0.0357)≈0.111, i.e. 11%, so D. Correct answers: A,B,D.