In a Vernier callipers, 1 cm of main scale has 20 divisions and 10 VSD coincide with 9 MSD. The Vernier constant is x×10⁻² mm. Find x.

Question

G1 Physics · Accepted Answer

1 MSD=1 cm/20=0.5 mm. 10 VSD=9 MSD, so 1 VSD=0.45 mm. Vernier constant=0.05 mm=5×10⁻² mm. Hence x=5.