The time period of a simple pendulum is T=2π√(ℓ/g). Measured ℓ=10.0±0.1 cm and T=0.50±0.02 s. Find the percentage error in g.

Question

G1 Physics · Accepted Answer

g=4π²ℓ/T², so percentage error =Δℓ/ℓ×100 +2ΔT/T×100 =0.1/10×100 +2(0.02/0.50×100)=1+8=9%. Answer: 9.