For a normal one-dimensional collision, impulse on each body is equal and opposite and e = |relative speed of separation|/|relative speed of approach|. In the shown case a 2 kg block moves at 6 m s⁻¹ and a 1 kg block at 4 m s⁻¹ in the same direction before collision.

Physics · Center of maas , Momentum and Collision · collision and types of collision

JEE Advanced

For a normal one-dimensional collision, impulse on each body is equal and opposite and e = |relative speed of separation|/|relative speed of approach|. In the shown case a 2 kg block moves at 6 m s⁻¹ and a 1 kg block at 4 m s⁻¹ in the same direction before collision.

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Sub-question 1

If the collision is elastic, the impulse magnitude J is:

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Sub-question 2

For what value of J will the 2 kg block change direction?

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