A glass slab is inserted between the plates of an isolated charged parallel-plate capacitor. Which quantity does not change?
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A glass slab is inserted between the plates of an isolated charged parallel-plate capacitor. Which quantity does not change?

G1 Physics · Accepted Answer

The capacitor is isolated, so no charge can enter or leave: Q remains constant. Inserting dielectric increases C and therefore reduces V, E and U=Q²/(2C). Correct answer: D.