The dimension of ½ ε₀E², where ε₀ is permittivity of free space and E is electric field, is:
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Question

The dimension of ½ ε₀E², where ε₀ is permittivity of free space and E is electric field, is:

G1 Physics · Accepted Answer

Step 1: [ε₀]=[M⁻¹ L⁻³ T⁴ A²] and [E]=[M L T⁻³ A⁻¹]. Step 2: Therefore [ε₀E²]=[M L⁻¹ T⁻²], the dimension of energy density. Final: Hence option B.