The ratio of the distances travelled by a freely falling body in the 1st, 2nd, 3rd and 4th second is:
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Question

The ratio of the distances travelled by a freely falling body in the 1st, 2nd, 3rd and 4th second is:

G1 Physics · Accepted Answer

Step 1: Distance covered in the nth second for uniform acceleration is sₙ = u + ½a(2n−1). Step 2: For free fall from rest, u=0 and a=g, so sₙ ∝ (2n−1). Step 3: For n=1,2,3,4 the ratio is 1:3:5:7. Final answer: B.