Two particles move with initial speeds of 4 m s⁻¹ and 2 m s⁻¹ and their accelerations are 1 m s⁻² and 2 m s⁻² respectively. If both reach the final position in the same time, then the length of path travelled is:
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Question

Two particles move with initial speeds of 4 m s⁻¹ and 2 m s⁻¹ and their accelerations are 1 m s⁻² and 2 m s⁻² respectively. If both reach the final position in the same time, then the length of path travelled is:

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G1 Physics · Accepted Answer

Step 1: Let common time be t and path length be s. First particle: s=4t+½t². Second particle: s=2t+t². Step 2: Equating gives 4t+½t²=2t+t², so t=4 s. Step 3: s=4×4+½×16=24 m. Final answer: B.