A particle is moving such that its position coordinates (x,y) are (2 m, 3 m) at t=0, (6 m, 7 m) at t=2 s and (13 m, 14 m) at t=5 s. The average velocity vector from t=0 to t=5 s is:
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Question

A particle is moving such that its position coordinates (x,y) are (2 m, 3 m) at t=0, (6 m, 7 m) at t=2 s and (13 m, 14 m) at t=5 s. The average velocity vector from t=0 to t=5 s is:

G1 Physics · Accepted Answer

Step 1: Initial position is 2i+3j and final position is 13i+14j. Step 2: Net displacement = 11i+11j m. Step 3: Average velocity = displacement/time = (11/5)(i+j) m s⁻¹. Final answer: D.