300 J of work slides a 2 kg block up an inclined plane by height 10 m. How much work is done against friction? Use g=10 m s⁻².
Options

Question

300 J of work slides a 2 kg block up an inclined plane by height 10 m. How much work is done against friction? Use g=10 m s⁻².

G1 Physics · Accepted Answer

Step 1 — Principle: Applied work is spent on gravitational potential-energy gain and on overcoming resistive forces. Step 2 — Working: Increase in gravitational PE=mgh=2×10×10=200 J. Step 3 — Working: Applied work=300 J. Step 4 — Working: Remaining energy lost to friction=300−200=100 J. Correct answer: C — 100 J.