Find energy ideally radiated by a 100 kW transmitter in 1 hour.

Question

G1 Physics · Accepted Answer

Step 1 — Principle: Energy delivered over a time interval is E = Pt for constant power. Step 2 — Working: Energy=power×time=(100×10³ W)(3600 s)=3.6×10⁸ J=36×10⁷ J. Correct answer: D — 36×10⁷ J.