A uniform 200 cm, 500 g rod is balanced on a wedge at its 40 cm mark. Mass 2 kg hangs at 20 cm and mass m hangs at 160 cm as shown. Find m (g=10 m/s²).
Physics · Rotational Motion · torque and rotational equilibrium
A uniform 200 cm, 500 g rod is balanced on a wedge at its 40 cm mark. Mass 2 kg hangs at 20 cm and mass m hangs at 160 cm as shown. Find m (g=10 m/s²).
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